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Algebra help

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Postby PackerAttack84 » Fri May 06, 2005 6:56 am

Canadian_Cheesehead wrote:I'm taking Gr.12 Calculus right now, and just like all this crap, it serves no purpose in the real world. Its a waste of my freaking time.


You're not the only one thinking that. There are times that we do the most pointless stuff and it's like, so when exactly will I need this again, and a higher math class doesn't count.
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Postby hastur » Fri May 06, 2005 11:51 am

Sorry, math was never my strong point.

I can conjugate the @#$! out of a verb though!
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Postby PackerAttack84 » Fri May 06, 2005 3:17 pm

The oddest thing just happened, we just started to learn this stuff today in our Algebra class, ironic, the day before you post this, and then the next day I start to do it in my Algebra class.
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Postby mtryanks12 » Fri May 06, 2005 3:24 pm

Just so you guys know, I just took an algebra test on polynominals and I got a 90!!!!!! Finally a good grade in math. I have one question about a problem that I got wrong.

The problem:

5x^2(7x+9)=0

I ran out of time, so I just wrote not possible, but I just did it and I wanna know if it is right.

5x^2(7x+9)=0

x has to =0, so that's one answer, but what's the other??
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Postby portisfan24 » Fri May 06, 2005 4:13 pm

well ya 0 is correct. Then you would find 0 for in the brackets.

7x+9=0
7x=-9
x=-9/7

Not sure if thats the proper method but it is an answer.
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Postby KPucks » Fri May 06, 2005 5:18 pm

mtryanks12 wrote:I also have to make correction to a test I ed, so this is another.

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note that the # in the far left is a 3.

I think that x may equal -6. am I right??


Using a graphing calculator, the answer is about x = 4.9863563. Can you use a calculator or do you have solve it algebraically?
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Postby Mercer Boy » Fri May 06, 2005 7:18 pm

portisfan24 wrote:well ya 0 is correct. Then you would find 0 for in the brackets.

7x+9=0
7x=-9
x=-9/7

Not sure if thats the proper method but it is an answer.


This is indeed the answer. ;-D

All you have to do is divide both sides by 5x^2...that leaves you with 7x+9 = 0 (because anything divided by zero is zero). Then you solve for x like you would normally.
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Postby Goatwhacker » Fri May 06, 2005 8:46 pm

Mercer Boy wrote:
All you have to do is divide both sides by 5x^2...that leaves you with 7x+9 = 0 (because anything divided by zero is zero).


You mean multiplied - anything divided by zero is infinity.
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Postby Mercer Boy » Fri May 06, 2005 8:59 pm

Bleh, by 0, into 0...you get what I mean. 0 / 5x^2 = 0. :-)
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