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Riddle me this Commish...who wins this tiebreaker?

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Riddle me this Commish...who wins this tiebreaker?

Postby BeefSandwiches » Tue Nov 28, 2006 6:09 pm

In my league, head-to-head is the first tie breaker when teams finish tied in the standings. If this week goes how I think it will, I will have 4 teams in the same division finish at 6-7. Typically in this situation division teams split their season series and the tie-breaker is decided by points but get this:

Teams A, B, C and D are all 6-7...

TEAM A - beat Team B twice, beat Team C twice
TEAM B - beat Team C twice
TEAM C - beat Team D twice
TEAM D - beat Team A twice

Who wins this tie-breaker? I would love to make it easy and revert to points, but it doesn't seem fair that one team could miss the playoffs if they beat a team that made the playoffs twice and had the same overall record.

HELP!! :-o
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Postby woodson_28 » Tue Nov 28, 2006 6:11 pm

I'd rank them this way, from 1st the last (1st going to playoffs)

1. Team A
2. Team D
3. Team B
4. Team C
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Postby Matthias » Tue Nov 28, 2006 6:20 pm

In this kind of situation, you don't have a "Head to Head" winner to determine the tiebreaker. Go to tiebreaker #2.
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Postby Battlecreek Dragon » Tue Nov 28, 2006 6:27 pm

We break ties when teams have the same overall season record as follows:

#1 Division Record
#2 Head to Head
#3 FP Scored

I'm not sure you have provided enough information. Do we assume there are no other teams in this division? What is Team D's record versus Team B? (Split)?

Based on the information provided it seems that Team A should win the tie breaker, but you have to go by what your rules say regardless of how fair it seems. Rules are rules and if you go changing them based on "fairness" you will cause problems.
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Postby skinsfan » Tue Nov 28, 2006 6:33 pm

1. Team A
2. Team D
3(t). Team C
3(t). Team B

Let points decide the last two.
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Postby Matthias » Tue Nov 28, 2006 6:35 pm

Yah, but Team D beat Team A twice, so how can Team A be over it? And for that matter, Team C beat Team D beat twice, so how can you justify putting D over C?
Last edited by Matthias on Tue Nov 28, 2006 6:41 pm, edited 1 time in total.
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Postby Peacesells » Tue Nov 28, 2006 6:37 pm

There is no such thing as a head to head tie breaker between 4 teams. Head to head by definition involves 2 teams. Just go to your next tie breaker rule. If you don't have one use the NFL rules which I believe states record versus common opponents. You can find it on NFL.com.

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Postby Battlecreek Dragon » Tue Nov 28, 2006 6:41 pm

Matthias wrote:Yah, but Team D beat Team A twice, so how can Team A be over it?


I probably should not have drawn a conclusion based on information I already questioned as incomplete. My conclusion was based soley on the statement that Team A has 4 wins versus the other three teams and none of the other teams have disclosed wins totaling more than 2 versus the other three.

We need more information!
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Postby EagleFan68 » Tue Nov 28, 2006 7:12 pm

Our first tie breaker in the standings AND if a playoff game happens to end in a tie is always most total points scored to date.


Why?

Because that is what fanatasy football is all about, the points scored.
[b]QB's [/b] E. MANNING / KITNA / CUTLER
[b]RBs[/b] R BROWN / WESTBROOK (R BUSH / MCGAHEE / L BETTS / D WILLIAMS )
[b]WRs[/b] ROY WILLIAMS / T OWENS / A JOHNSON / BERRIAN
[b]TE[/b] WITTEN / WATSON
[b]K[/b] GRAHAM
[b]DT[/b] PANTHERS
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Re: Riddle me this Commish...who wins this tiebreaker?

Postby woodson_28 » Tue Nov 28, 2006 7:21 pm

BeefSandwiches wrote:
TEAM A - beat Team B twice, beat Team C twice
TEAM B - beat Team C twice
TEAM C - beat Team D twice
TEAM D - beat Team A twice


a, d, b, c

1. Team A is first because it has the most divisional wins (beating B and C twice)

2. Team D comes in second because he beat the #1 team (Team A).

3. Team B comes in third, because team B and C are left, and Team B beat Team C twice.

4. Thus Team C is forth.

That's how I would do it based off the information you provided.
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