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Riddle me this Commish...who wins this tiebreaker?

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Re: Riddle me this Commish...who wins this tiebreaker?

Postby Matthias » Tue Nov 28, 2006 7:25 pm

woodson_28 wrote:
BeefSandwiches wrote:
TEAM A - beat Team B twice, beat Team C twice
TEAM B - beat Team C twice
TEAM C - beat Team D twice
TEAM D - beat Team A twice


a, d, b, c

1. Team A is first because it has the most divisional wins (beating B and C twice)

2. Team D comes in second because he beat the #1 team (Team A).

3. Team B comes in third, because team B and C are left, and Team B beat Team C twice.

4. Thus Team C is forth.

That's how I would do it based off the information you provided.


That logic is fine but it's not considering Head to Head record, but rather most divisional wins, or who beat you consider the #1 team or whatever. Really, the answer is: the winner cannot be determined from this situation by going by Head to Head. You go to your next tiebreaker.
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Re: Riddle me this Commish...who wins this tiebreaker?

Postby BeefSandwiches » Tue Nov 28, 2006 7:35 pm

Matthias wrote:That logic is fine but it's not considering Head to Head record, but rather most divisional wins, or who beat you consider the #1 team or whatever. Really, the answer is: the winner cannot be determined from this situation by going by Head to Head. You go to your next tiebreaker.


This is what I figured I would have to do, but I wanted to get some other opinions on it. I don't think there is any choice to use anything except the next tie-breaker.
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Postby mattb47 » Tue Nov 28, 2006 7:40 pm

I think it should be decided by record against the division personally. It is how it is done in most leagues that use divisions to break up the league and it would be the most fair deciding factor I think. If that is still a wash then go with most points. It doesn't matter what you choose, someone will be upset about it, so just go with one and stick with it.
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Postby buffalobillsrul2002 » Tue Nov 28, 2006 8:45 pm

It all depends on how team B did vs. team D....

If Team B did not play Team D twice...

Go to the next tiebreaker. Head-to-head only works when all teams have equal # of games played vs. each other

If team B beat Team D twice...

1. Team A (4-2, beat Team B twice)
2. Team B (4-2, lost to Team A)
3. C (2-4, beat Team D)
4. D

If team B and team D split

1. Team A (4-2)
2. Team B/Team D (both 3-3, split head-to-head, use next TB to determine this)
3. Loser of Team B/Team D
4. Team C

If Team D beat Team B twice..

1. Team D(4-2, beat Team A twice)
2. Team A(4-2)
3. Team B (2-4, beat C twice)
4. C
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Postby Timbathia » Tue Nov 28, 2006 8:50 pm

Totally agree with the earlier post that:

H2H CANNOT decide this...

so you go to your next tiebreaker, which as you said is most points.
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Postby Azrael » Tue Nov 28, 2006 11:07 pm

paper, rock, scissors tournament
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Postby Timbathia » Wed Nov 29, 2006 12:30 am

Azrael wrote:paper, rock, scissors tournament


so long as it is best of three - you got to take the luck out of it.
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Postby lmcjaho » Wed Nov 29, 2006 3:40 am

**This comment brought to you by BrutallyHuge***

Just give the playoff spots to the teams least likely to beat yours.
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Postby The Balanced Man » Wed Nov 29, 2006 8:38 am

Timbathia wrote:Totally agree with the earlier post that:

H2H CANNOT decide this...

so you go to your next tiebreaker, which as you said is most points.


I agree here.

I'm doing a piece about this on Friday's edition of The Coach's Voice. feel free to check it out.
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